Group 13 and 14 Elements
P-block Elements: Group 13 and 14 Elements
Group 13 and 14 Elements
Group 13 and 14 Elements
What you'll learn
- Distinguish the key compounds of boron (borax, boric acid, diborane) and explain their structures and reactions
- Explain why aluminium forms alums and how thermite reaction works
- Compare allotropes of carbon — graphite, diamond, and fullerene — in terms of structure and properties
- Describe the chemistry of silicon: silicones, silicates, and their industrial uses
- Write and balance reactions of CO, CO₂, and SiO₂ and predict their acidic/basic character
- Identify JEE-level traps in oxidation states, hybridisation, and anomalous behaviour of B and C
Key concepts
Level 1 — Foundations
Group 13 — The Boron Family
| Property | B | Al | Ga | In | Tl |
|---|---|---|---|---|---|
| Atomic radius (pm) | 87 | 143 | 135 | 167 | 170 |
| First IE (kJ/mol) | 801 | 577 | 579 | 558 | 589 |
| Oxidation state | +3 | +3 | +1, +3 | +1, +3 | +1 (+3 rare) |
| Nature | Metalloid | Metal | Metal | Metal | Metal |
Boron — Key Compounds
| Compound | Formula | Key Facts |
|---|---|---|
| Borax | Na₂B₄O₇·10H₂O | Bead test; buffer; softens water |
| Boric acid | H₃BO₃ | Weak monobasic Lewis acid; layered structure |
| Diborane | B₂H₆ | Electron-deficient; 3-centre 2-electron (banana) bonds |
| Boron nitride | BN | Hexagonal (h-BN) or cubic (c-BN, hardest after diamond) |
Borax bead test: Heat borax → loses water → fuses to glassy bead of metaboric acid, then B₂O₃. Dissolve metal oxides in this bead; colour identifies the metal.
Boric acid as Lewis acid:
H₃BO₃ + H₂O → [B(OH)₄]⁻ + H⁺
It accepts OH⁻ from water (Lewis mechanism), not a Brønsted acid directly.
Diborane structure:
- 12 electrons, 8 bonds needed but only 12 electrons → 3c-2e bonds
- 2 bridging H atoms (Hb), 4 terminal H atoms (Ht)
- B–Hb–B bridges are "banana bonds"
- Each B is sp³ hybridised
Aluminium
Thermite reaction:
Fe₂O₃ + 2Al → Al₂O₃ + 2Fe ΔH = −852 kJ/mol
Used for welding railway tracks.
Alums: M⁺M³⁺(SO₄)₂·12H₂O
Potash alum: KAl(SO₄)₂·12H₂O — used in water purification, dyeing.
Aluminium is amphoteric:
2Al + 6HCl → 2AlCl₃ + 3H₂↑
2Al + 2NaOH + 2H₂O → 2NaAlO₂ + 3H₂↑
Group 14 — The Carbon Family
| Property | C | Si | Ge | Sn | Pb |
|---|---|---|---|---|---|
| Hybridisation | sp, sp², sp³ | sp³ | sp³ | sp³ | sp³ |
| Common OS | −4 to +4 | +4, +2 | +4, +2 | +4, +2 | +2 (+4 rare) |
| Nature | Non-metal | Metalloid | Metalloid | Metal | Metal |
Carbon Allotropes
| Allotrope | Structure | Hybridisation | Properties |
|---|---|---|---|
| Diamond | 3D tetrahedral network | sp³ | Hardest natural substance; insulator; high MP |
| Graphite | Layered hexagonal sheets | sp² | Soft; conductor; lubricant; π electrons mobile |
| Fullerene (C₆₀) | Truncated icosahedron (soccer ball) | sp² | 20 hexagons + 12 pentagons; superconductor when doped |
| Graphene | Single graphite sheet | sp² | Strongest 2D material; excellent conductor |
CO and CO₂
| Property | CO | CO₂ |
|---|---|---|
| Structure | Linear (triple bond) | Linear (two C=O) |
| Nature | Neutral oxide | Acidic oxide |
| Oxidation state of C | +2 | +4 |
| Key reaction | CO + Cl₂ → COCl₂ (phosgene) | CO₂ + H₂O → H₂CO₃ |
| Ligand behaviour | Strong π-acceptor in carbonyls | No |
CO is a reducing agent:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Silicon Compounds
Silica (SiO₂):
- Giant covalent structure (unlike CO₂ which is molecular)
- Each Si bonded to 4 O; each O bridging 2 Si
- Reacts with HF: SiO₂ + 4HF → SiF₄ + 2H₂O (used to etch glass)
- Reacts with NaOH (fused): SiO₂ + 2NaOH → Na₂SiO₃ + H₂O
Silicates: Based on SiO₄⁴⁻ tetrahedra linked in chains, sheets, or 3D networks.
| Silicate type | Units | Example |
|---|---|---|
| Orthosilicate | Isolated SiO₄⁴⁻ | Olivine (Mg₂SiO₄) |
| Pyrosilicate | Si₂O₇⁶⁻ | Thortveitite |
| Chain | (SiO₃²⁻)ₙ | Asbestos |
| Sheet | (Si₂O₅²⁻)ₙ | Mica, talc |
| 3D network | SiO₂ | Quartz |
Silicones: Synthetic organosilicon polymers
General unit: (R₂SiO)ₙ
Made by hydrolysis of R₂SiCl₂ followed by condensation polymerisation.
Properties: water-repellent, thermally stable, electrical insulators.
Level 2 — JEE Depth
Anomalous behaviour of Boron (vs Al):
- B is a metalloid; Al is a metal
- B forms only covalent compounds; Al forms ionic + covalent
- B does not react with steam or dilute acids easily; Al does
- B has no d-orbitals → maximum covalency 4 (in [BF₄]⁻); Al can expand octet
Why is BF₃ a Lewis acid despite B–F bond being strong?
B is electron-deficient (only 6e⁻ around B). The empty p-orbital accepts lone pairs. Despite partial back-donation from F (p→p π), BF₃ is still a Lewis acid.
Lewis acid strength: BF₃ > BCl₃ > BBr₃ (back-bonding decreases, so Lewis acidity increases down).
Inert pair effect in Group 14:
Going down (Ge → Sn → Pb), the +2 state becomes more stable because the 6s² pair is reluctant to participate in bonding.
PbO₂ is a stronger oxidising agent than SnO₂.
Graphite vs Diamond — JEE trap:
Graphite is thermodynamically more stable than diamond at room temperature and pressure (ΔG for diamond → graphite is slightly negative), yet diamond persists because the activation energy for conversion is enormous.
Fullerene (C₆₀) — bond lengths:
C–C between two hexagons: 1.40 Å (double bond character)
C–C between hexagon and pentagon: 1.45 Å (single bond character)
SiO₂ vs CO₂ — structural difference (JEE favourite):
CO₂ forms discrete molecules (pπ–pπ bonding between C and O is effective).
SiO₂ forms a network solid (Si cannot form effective pπ–pπ bonds due to large size and diffuse 3p orbitals → forms σ bonds via sp³ hybridisation).
Hybridisation of carbon in key compounds:
| Compound | Hybridisation of C |
|---|---|
| CH₄ | sp³ |
| C₂H₄ | sp² |
| C₂H₂ | sp |
| CO₂ | sp |
| CO | sp (formally) |
| Graphite | sp² |
| Diamond | sp³ |
Worked example
Example 1: Identify the product when excess NaOH reacts with Al₂O₃ and write the reaction.
Step 1: Recognise that Al₂O₃ is an amphoteric oxide.
Step 2: With a base (NaOH), it behaves as an acidic oxide.
Step 3: Reaction:
Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O
(sodium aluminate)
Step 4: In excess NaOH (aq), the product is [Al(OH)₄]⁻:
Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄]
Answer: Sodium tetrahydroxoaluminate(III)
Example 2: Calculate the number of 3-centre 2-electron bonds in diborane (B₂H₆).
Step 1: Count total valence electrons:
2B × 3e⁻ = 6e⁻
6H × 1e⁻ = 6e⁻
Total = 12e⁻
Step 2: Structure has:
- 4 terminal B–H bonds (normal 2c-2e): 4 × 2 = 8e⁻ used
- 2 bridging B–H–B bonds: 2 × 2 = 4e⁻ used
Total = 12e⁻ ✓
Step 3: Each B–H–B bridge is a 3-centre 2-electron bond.
Answer: 2 three-centre two-electron (banana) bonds in B₂H₆.
Common mistakes
| Mistake | Why it happens | Fix |
|---|---|---|
| Calling boric acid a Brønsted acid (proton donor) | It looks like H₃BO₃ has acidic H | It is a Lewis acid — accepts OH⁻ from water, then releases H⁺ |
| Saying graphite is less stable than diamond | Diamond is harder, so assumed more stable | Graphite has lower Gibbs energy at STP; hardness ≠ thermodynamic stability |
| Forgetting SiO₂ is a network solid, not molecular | Analogy with CO₂ (molecular gas) | Si can't form pπ–pπ bonds; forms sp³ network instead |
| Confusing Lewis acid strength order for BX₃ | Expecting more electronegative F to withdraw more → stronger acid | Back-donation F>Cl>Br reduces Lewis acidity; actual order BF₃ < BCl₃ < BBr₃ |
| Writing diborane as two separate BH₃ units | BH₃ is the monomer but B₂H₆ has bridging H | Always draw/mention the two 3c-2e B–H–B bridges |
Quick check
- Q1: Why does boron form only covalent compounds but aluminium forms ionic compounds too?
- Q2: Write the reaction of borax with HCl. What is the product?
- Q3: Which allotrope of carbon is used as a lubricant and why?
- Q4: Give one chemical distinction between SiO₂ and CO₂ with a reaction.
- Stretch: Q5: The Lewis acid strength order of boron trihalides is BF₃ < BCl₃ < BBr₃. Explain using back-bonding concepts and predict whether BI₃ would be a stronger or weaker Lewis acid than BBr₃.
NCERT Chapter 11 link: P-Block Elements (Part I — Groups 13 and 14), NCERT Chemistry Part 1, Class 12
Exam connections: JEE Mains frequently tests borax bead test, diborane structure, allotropes of carbon, and SiO₂ vs CO₂ comparison. JEE Advanced has asked mechanistic questions on Lewis acidity of BX₃ and inert pair effect.
Study strategy: Build a comparison table for each group (B vs Al, C vs Si vs Pb). Draw structures of diborane, diamond, graphite, and fullerene from memory. For reactions, group them: "with water", "with acid", "with base", "with oxidising agent."
Interactive Exploration Suggestions (Drishti Live Worlds)
- Use the platform-native live simulation or PhET-style tool for this topic.
- Mirror / body / home activity: physically do the concept and photograph or describe for portfolio.
- Voice or text reflection with AI Mentor: explain the concept to a younger student or family member.
AI Mentor Prompts (Socratic, Board-Adaptive)
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- Coding extension where relevant (simple script, simulation, or data logging).
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Portfolio Evidence Idea: Your photo/table/reflection/project + one sentence on "How this helps me in real life or a possible future path."
Open the Practice tab for aligned questions (easy/medium/hard + case-based) with full AI scaffolding.
See curriculum for cross-links and the full future-skills/robotics chapters.
Key Takeaways (TL;DR)
- What you'll learn
- Key concepts
- Worked example
- Common mistakes
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