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Icse Parallelogram Proofs

Geometry — Icse Parallelogram Proofs

Icse Parallelogram Proofs

Parallelogram Proofs (ICSE)

Key Properties of a Parallelogram

A parallelogram is a quadrilateral with two pairs of parallel opposite sides.

PropertyStatement
P1Opposite sides are equal: AB = CD, AD = BC
P2Opposite angles are equal: ∠A = ∠C, ∠B = ∠D
P3Adjacent angles are supplementary: ∠A + ∠B = 180°
P4Diagonals bisect each other: AO = OC, BO = OD (O = intersection)
P5Each diagonal divides the parallelogram into two congruent triangles

Proof 1: Opposite Sides are Equal (P1)

Given: ABCD is a parallelogram (AB ∥ CD, AD ∥ BC) To prove: AB = CD and AD = BC

Construction: Draw diagonal AC.

Proof: In △ABC and △CDA:

  • ∠BAC = ∠DCA (alternate interior angles, AB ∥ DC, AC is transversal)
  • ∠BCA = ∠DAC (alternate interior angles, BC ∥ AD, AC is transversal)
  • AC = AC (common side)

∴ △ABC ≅ △CDA (by ASA) ∴ AB = CD and BC = AD (CPCT) QED

Proof 2: Diagonals Bisect Each Other (P4)

Given: ABCD is a parallelogram, diagonals AC and BD intersect at O To prove: AO = OC and BO = OD

In △AOB and △COD:

  • ∠OAB = ∠OCD (alternate angles, AB ∥ CD)
  • ∠OBA = ∠ODC (alternate angles, AB ∥ CD)
  • AB = CD (proved above)

∴ △AOB ≅ △COD (by ASA) ∴ AO = OC and BO = OD (CPCT) QED

Proof 3: Converse — If Diagonals Bisect Each Other, It's a Parallelogram

Given: Quadrilateral ABCD with diagonals bisecting each other at O (AO = OC, BO = OD) To prove: ABCD is a parallelogram

In △AOB and △COD:

  • AO = OC (given)
  • BO = OD (given)
  • ∠AOB = ∠COD (vertically opposite angles)

∴ △AOB ≅ △COD (SAS) ∴ AB = CD and ∠OAB = ∠OCD → AB ∥ CD

Similarly, △AOD ≅ △COB → AD = BC and AD ∥ BC ∴ ABCD is a parallelogram. QED

Special Parallelograms

ShapeExtra Property
RectangleAll angles = 90°; diagonals equal
RhombusAll sides equal; diagonals perpendicular bisectors
SquareAll sides equal + all angles 90°; diagonals equal + perpendicular

ICSE Proof Technique Tips

  1. State given information clearly
  2. Identify which triangles to prove congruent
  3. Name the congruence criterion: SSS, SAS, ASA, AAS, RHS
  4. Use CPCT (corresponding parts of congruent triangles) to extract what you need
  5. Write QED (quod erat demonstrandum) at the end

Standard ICSE Proof Question Types

  • Prove that the diagonals of a rhombus bisect each other at right angles
  • In parallelogram ABCD, E and F are midpoints of AB and CD — prove AFCE is a parallelogram
  • Prove that the line segment joining midpoints of two sides of a triangle is parallel to the third side (Midpoint Theorem)

Quick Check

  1. In parallelogram PQRS, ∠P = 70°. Find all other angles.
  2. If diagonals of a quadrilateral bisect each other, what can you conclude? Why?
  3. In rhombus ABCD, the diagonals meet at O. Prove that ∠AOB = 90°.
  4. State the condition that makes a parallelogram a rectangle.
  5. Stretch: ABCD is a parallelogram and E is the midpoint of AB. DE extended meets BC extended at F. Prove that DF = 2 × DE.

Key Takeaways (TL;DR)

  • Key Properties of a Parallelogram
  • Proof 1: Opposite Sides are Equal (P1)
  • Proof 2: Diagonals Bisect Each Other (P4)
  • Proof 3: Converse — If Diagonals Bisect Each Other, It's a Parallelogram

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