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Colligative

Comprehensive notes, formulas, and practice questions for Colligative.

Colligative

Colligative Properties

What you'll learn

  • Colligative properties depend on number of solute particles, not identity.
  • Relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, osmotic pressure.
  • Formulas: ΔT_b = K_b m, ΔT_f = K_f m, π = MRT (dilute solutions).
  • van't Hoff factor i for electrolytes: i = observed particles / formula units.
  • Determine molar mass from colligative measurements — classic NEET numerical.

Key concepts

Level 1 — Foundations

Verbal: Colligative properties arise from adding solute that alters solvent chemical potential — effects scale with molal concentration of particles.

Four properties (NCERT):

  1. Relative lowering of vapour pressure: Δp/p° = i χ_solute
  2. Boiling point elevation: ΔT_b = i K_b m
  3. Freezing point depression: ΔT_f = i K_f m
  4. Osmotic pressure: π = i MRT ≈ i cRT

Molality m used in ΔT formulas (temperature-stable).

Osmotic pressure: Most sensitive for macromolecules — determine M from π.

Level 2 — JEE / NEET depth

van't Hoff factor i:

Solute typei (ideal)Example
Non-electrolyte1glucose
Strong electrolyte AB2NaCl → Na⁺ + Cl⁻
AB₂3CaCl₂
Association< 1carboxylic acid dimer

Abnormal molar mass: i < 1 association; i > 1 dissociation — measured molar mass deviates.

Osmosis: Solvent flows through semipermeable membrane to dilute side; equilibrium when π equals applied pressure.

Reverse osmosis: Pressure > π forces desalination.

JEE strategy: Identify i first; use molality for ΔT; use molarity in π with dilute assumption; watch units (K_kg/mol for K_b, K_f).

Worked example

Freezing point depression

Dissolve 0.5 mol glucose in 1 kg water. K_f = 1.86 K·kg/mol, i = 1.

Step 1 — m = 0.5 mol/kg.
Step 2 — ΔT_f = i K_f m = 1 × 1.86 × 0.5 = 0.93 K.
Step 3 — New freezing point ≈ 273.15 − 0.93 = 272.22 K (−0.93°C).
Step 4 — Salt on roads uses same principle with higher i.

Osmotic pressure molar mass

π = 2.5 atm at 300 K for protein solution c = 0.01 M (i = 1). Verify consistency R = 0.0821 L·atm/mol·K.

Step 1 — π = MRT → M = π/(RT) = 2.5/(0.0821×300) ≈ 0.102 M.
Step 2 — Given c = 0.01 M discrepancy suggests large molar mass macromolecule measured differently or aggregation — typical exam gives mass directly from π = (mass/V)RT/M rearranged.
Step 3 — Standard: M = mRT/(πV) for mass m in volume V.

Common mistakes

MistakeWhy it happensFix
Using molarity in ΔT_f without justificationMixing unitsΔT formulas use molality m
Forgetting i for NaCli = 1 for all solutesStrong electrolytes: i = number of ions (ideal limit)
Sign error on freezing pointAdding ΔT_f to freezeFreezing point decreases: T_f = T_f° − ΔT_f
Wrong R unit in π = MRTJ vs atmMatch R with pressure units (0.0821 L·atm/mol·K)

Quick check

  • List four colligative properties.
  • ΔT_b for 1 m NaCl (i=2), K_b=0.52?
  • Why is osmotic pressure sensitive for polymers?
  • Define van't Hoff factor.
  • Stretch: Calculate molar mass from ΔT_f data with given K_f and solvent mass.

NCERT Chapter 2 link: Colligative properties depend on particle count — electrolyte dissociation increases effect via van't Hoff factor i. Abnormal molar mass from colligative measurement reveals dissociation or association.

Exam connections: ΔT_b = iK_b m and ΔT_f = iK_f m — molality always. Osmotic pressure π = iMRT most sensitive for macromolecules — calculate molar mass from π data. Determine i from observed vs expected colligative change.

Study strategy: Decision tree: identify solute type → assign i → choose formula → watch units (K_b in K·kg/mol, R with atm or Pa consistently). For glucose i=1; NaCl ideally i=2; CaCl₂ ideally i=3.

Study workflow and exam preparation

When studying Colligative Properties within Solutions, start by listing every formula and definition on one page without looking at the textbook. Compare your list to NCERT — missing items indicate gaps to fix immediately. Work through at least two NCERT Examples for this section with steps written in full; examiners award method marks even when arithmetic slips.

For board exams (CBSE), long answers benefit from a clear structure: definition → explanation → diagram or formula → example → brief conclusion. Underline key terms. For JEE Main and NEET, prioritise conceptual traps and quick calculation paths; timed mixed quizzes of 10 questions after revision simulate exam pressure.

Cross-topic link: Stoichiometry from Class 11 mole concept underpins solution and electrochemistry numericals.

Spaced revision: Review this note at 1 day, 3 days, and 7 days after first study. Attempt the Quick check questions closed-book, then open the Practice tab for graded reinforcement. Maintain an error log — repeated mistake patterns reveal whether the issue is concept, formula recall, or careless reading.

Diagram and terminology drill: For Chemistry, redraw key figures from memory and define every labelled part in one sentence. Vocabulary precision prevents mark loss in descriptive answers — use NCERT terms exactly as printed in the textbook.

Revision tip: Link this topic to adjacent Class 12 chapters before attempting mixed practice.

Open the Practice tab for graded questions on Colligative Properties.

Key Takeaways (TL;DR)

  • What you'll learn
  • Key concepts
  • Worked example
  • Common mistakes

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