Rules
Comprehensive notes, formulas, and practice questions for Rules.
Rules
Differentiation Rules
What you'll learn
- The sum, difference, and constant multiple rules for rapid differentiation without first principles every time.
- The product rule and quotient rule for combined functions — JEE staples.
- The chain rule for composite functions f(g(x)).
- To differentiate polynomials, rational functions, and simple trigonometric expressions efficiently.
Key concepts
Level 1 — Linearity and power rule
Verbal: Differentiation is linear: the derivative of a sum is the sum of derivatives, and constants factor out.
Symbolic:
- (u ± v)′ = u′ ± v′
- (cu)′ = c u′
- (xⁿ)′ = n xⁿ⁻¹ (n real, NCERT focus on integer n)
Examples:
- d/dx(4x³ − 7x + 1) = 12x² − 7
- d/dx(√x) = d/dx(x^(1/2)) = (1/2)x^(−1/2) = 1/(2√x)
Level 2 — Product, quotient, and chain rules
| Rule | Formula | Example |
|---|---|---|
| Product | (uv)′ = u′v + uv′ | (x² sin x)′ = 2x sin x + x² cos x |
| Quotient | (u/v)′ = (u′v − uv′)/v² | (sin x/x)′ = (x cos x − sin x)/x² |
| Chain | d/dx f(g(x)) = f′(g(x))·g′(x) | d/dx sin(3x) = 3 cos(3x) |
Trig derivatives (with chain):
- (sin x)′ = cos x; (cos x)′ = −sin x
- (tan x)′ = sec²x; (cot x)′ = −cosec²x
Strategy: Identify outer and inner functions for chain rule. For rational functions, quotient rule or simplify first.
NCERT Class 11 scope: Emphasis on product and quotient for low-degree polynomials with sin/cos; full chain rule extended in Class 12.
NCERT spotlight — Chain rule and beyond
For y = sin(3x), inner function 3x gives dy/dx = 3 cos(3x). Quotient rule on (sin x)/x produces (x cos x - sin x)/x squared. Parametric motion uses dy/dx = (dy/dt)/(dx/dt).
Implicit differentiation preview: From x squared + y squared = 25, obtain dy/dx = -x/y without solving for y explicitly.
Critical points: Solve f prime (x) = 0 to locate candidates for maxima and minima in optimisation problems.
Worked example
Differentiate y = (2x + 1)³ · sin x.
Step 1 — Product rule: y′ = u′v + uv′ with u = (2x+1)³, v = sin x.
Step 2 — Chain on u: u′ = 3(2x+1)² · 2 = 6(2x+1)².
Step 3 — v′ = cos x.
Step 4 — y′ = 6(2x+1)² sin x + (2x+1)³ cos x
= (2x+1)² [6 sin x + (2x+1) cos x].
Step 5 — Factorisation helps checking at x = 0: y′(0) = 1²[0 + 1·1] = 1.
Applications — related rates
Balloon radius r increasing at dr/dt = 2 cm/s. Volume V = (4/3) pi r cubed gives dV/dt = 4 pi r squared dr/dt. At r = 10 cm, dV/dt = 800 pi cm cubed/s. Chain rule links time rates of linked variables — classic JEE Main problem template requiring implicit differentiation of geometric formulas.
Common mistakes
| Mistake | Why it happens | Fix |
|---|---|---|
| (uv)′ = u′v′ | Treating like sum | Use u′v + uv′ |
| Forgetting inner derivative in chain rule | Missing g′(x) | Always multiply by derivative of inside |
| Quotient rule numerator order | Sign error | Remember u′v − uv′ |
| Differentiating before simplifying | Long algebra | Simplify function if possible first |
Deep dive — combined rules and optimisation setup
Differentiate y = x squared e to the x: product rule gives 2x e^x + x squared e^x = x e^x (x + 2). Quotient on tan x = sin x / cos x recovers sec squared x via quotient rule — verify against known derivative. Chain rule nested: sin(ln x) → derivative cos(ln x) × (1/x). Logarithmic differentiation for y = x to the x: ln y = x ln x → (1/y) y prime = ln x + 1 → y prime = x^x (ln x + 1). Second derivative f double prime for concavity: f double prime > 0 concave up. Velocity acceleration: if s = t cubed − 6t, v = 3t squared − 6, a = 6t — jerk is third derivative preview. Tangent normal problems combine rules with point evaluation — always find f prime then substitute x0. Class 12 extends to inverse trig, exponential log, implicit — Class 11 rules are foundation drilling product quotient chain until automatic.
Review and practice drill
Review checklist: (1) Product rule: first d second plus second d first. (2) Quotient rule: low d high minus high d low over low squared. (3) Chain rule: outer derivative times inner derivative. (4) Differentiate polynomials termwise. Practice: y = (x^2 + 1)^3 — chain gives 3(x^2+1)^2 times 2x.
Quick check
- Find dy/dx if y = x²/(x + 1).
- Differentiate f(x) = cos(5x − 2).
- If y = x·e^x (preview), product rule gives y′ = e^x + x e^x — verify pattern with (uv)′.
Open the Practice tab for graded questions on Rules.
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AI Mentor Prompts (Socratic, Board-Adaptive)
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- Coding extension where relevant (simple script, simulation, or data logging).
NEP 2020 & Full Education OS Alignment
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Portfolio Evidence Idea: Your photo/table/reflection/project + one sentence on "How this helps me in real life or a possible future path."
Open the Practice tab for aligned questions (easy/medium/hard + case-based) with full AI scaffolding.
See curriculum for cross-links and the full future-skills/robotics chapters.
Key Takeaways (TL;DR)
- What you'll learn
- Key concepts
- Worked example
- Common mistakes
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